Venezuela’s Opposition Leader was in Attendance at the State of the Union while President Trump Roasted Venezuela’s Socialist Government
Jose Nino
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Venezuelan opposition leader Juan Guaidó was in attendance at President Donald Trump’s third State of the Union address on February 4, 2020.
In his speech, Trump called out Venezuelan strongman Nicolás Maduro and declared that the head of the National Assembly, Juan Guaidó, is the true president of Venezuela.
“Here this evening is a man who carries with him the hopes, dreams, and aspirations of all Venezuelans,” Trump said.
“Joining us in the gallery is the true and legitimate President of Venezuela, Juan Guaidó. Mr. President, please take this message back that all Americans are united with the Venezuelan people in their righteous struggle for freedom,” Trump continued. “Socialism destroys nations. But always remember, freedom unifies the soul.”
Guaidó was seated near Ivanka Trump in a guest box designated for State of the Union guests. The White House did not make an announcement about Guaidó’s attendance in advance.
Trump thunderously declared that Maduro is “a tyrant who brutalizes” the Venezuelan populace and must relinquish his power to Guaidó.
Venezuela is the world’s latest failed socialist experiment and has caught the attention of international onlookers during the last decade.
Trump has made it a point to rhetorically attack countries such as Cuba, Nicaragua, and Venezuela for their socialist failures and use them as potential campaign fodder in states like Florida, where there is a substantial Cuban voting block with a strong anti-socialist streak.
This message will likely resonate with them given their experience with Cuban style tyranny and the Democrat Party’s lurch toward radicalism.
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